Pictures of TE O.J. Howard from Sunday's matchup against the Bills.
The NFL announced the honors following a breakout game against the Buffalo Bills this past Sunday that saw rookie tight end O.J. Howard score not only one, but two touchdowns on the day.
In a Week 7 matchup against one of the stingiest defenses in the NFL, quarterback Jameis Winston connected with Howard on a seven-yard touchdown grab in the third quarter for Tampa Bay's first touchdown on the day. The tight end wasn't done yet, as he nabbed a 33-yarder down the sideline for his second score. He finished the day with six catches for 98 yards.
Howard is averaging 18.6 yards a catch this season, with 205 yards on 11 receptions. He was the Buccaneers' first-round pick (19th overall) in the 2017 NFL Draft out of Alabama.
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